Understanding PDM and Pod Function 12
Example 4: Eating 60 g carbs, BG of 8.4 mmol/L is above target,
1 U correction IOB
Duration of Insulin Action = 2 hours.
One hour ago, you delivered a 2 U bolus to correct a high blood glucose. Because
you were not eating at that time and did not enter a carbohydrate value into the
Bolus Calculator, this was a 2 U correction bolus.
Now, one hour later, you are about to eat. There is a 1 U correction IOB from the
earlier bolus, and no meal IOB because you did not eat at the time of your last
bolus.
Correction bolus
BG = 8.4, Target BG = 5.6
Correction Factor = 2.8
(8.4-5.6) / 2.8 = 1 U
Meal IOB adjustment
Meal IOB = 0 U
1 U - 0 U = 1 U
Correction IOB adjustment
Correction IOB = 1 U
1 U - 1 U = 0 U
Meal bolus
Carbs = 60 g, IC Ratio = 15 g/U
60 / 15 = 4 U
Correction IOB adjustment
Remaining correction IOB = 0 U
4 U - 0 U = 4 U
Calculated bolus
Your adjustment
Total Bolus
0 U
Your blood glucose is 2.8
mmol/L over your target. A
correction factor of 2.8 gives a
1 U preliminary correction
bolus.
No meal IOB, so no meal IOB
adjustment.
The 1 U correction IOB reduces
the correction bolus to zero.
4 U
You are eating 60 g carbs.
An IC ratio of 15 gives a 4 U
preliminary meal bolus.
The entire correction IOB was
used to reduce the correction
bolus to zero, so no correction
IOB remains. The meal bolus
remains at 4 U.
4 U
The calculated bolus is entirely
a meal bolus. Even though your
0 U
blood glucose is above target,
the correction IOB reduced the
correction bolus to zero.
4 U
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Effective Date: 18OCT2020, PCO-000235