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Composition of the bending complement for medium and high series tubes
Delivered with 2 forms of 2"1/2 and 3" references 240122 and 240123, 2 shoes of 3"1/2 and 4" references
240124 and 240125 (see table page 16)
Components
Adaptor
Piston extension
Upper flange
Lower flange
Roller (x1)
Case 1625 x 310 x 680 mm
The 3"1/2 and 4" tubes are bent by points.
The bending radius "R" must be greater than or equal to 20 times the nominal diameter (DN) of the tube.
α
Ø
WARNING: Creating a bending radius "R" less than 20 times the nominal diameter "DN" generates too much effort
for the bender. This may damage the bender permanently.
Setting example:
- The tube diameter "Ø" = 4"
- The bending angle "α" = 90°
- The bending radius "R" = 20 x DN = 10 x 100 = 2000 mm
- The developed length "L" = 2 x PI x R x a/360
i.e. L = 2 x PI x R x 90/360 = 3140 mm
Then divided "L" into equal sectors. The length of each sector will be around 200 mm which corresponds to the developed
length for the 3"1/2 and 4" bending shoes.
3140/200 = 15,7
In fact, "L" will be divided into 16 sectors of 3140/16 = 196 mm.
Then trace the following information on the tube as indicated in the diagram below:
196 mm
1
Bending complement 240248
240205
240208
240223
240222
240117
240130
R
L
2
3
4
5
6
240248
•
•
•
•
••
•
Title
exterior Ø
3"1/2
4"
L = 3140 mm
7
8
9
10 11 12 13 14 15 16
DN
min R
mm
mm
101,6
90
1 800
114,3
100
2 000
EN
15
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