Ingeteam INGEREV SMART DLM Manuel D'installation Et Configuration page 11

INGEREV SMART DLM
KN: Transformer ratio (A)
Ratio between the rated current of the primary and the rated current of the secondary. It is expressed
as a fraction. For example: KN = (150 A / 5 A).
Cl: Accuracy class
The accuracy class is the percentage current error limit when operating at rated current.
Ingeteam requires the accuracy class of current transformers to be 0.5 (Cl 0.5).
It is also acceptable to use current transformers whose accuracy class allows current measurements
to be made with an error of less than that specified for accuracy class 0.5.
S : Precision power (VA)
n
This parameter describes the capacity of the transformer to pass a current through the secondary
through a load, while maintaining the accuracy class. It will be necessary to calculate the power
consumed in VA on the current transformer secondary (in this calculation, take into account the sum of
the wiring and the A65+ wattmeter).
We would recommend selecting a normalised power value that is as close as possible to the
calculated power, while the said normalised power must always be greater than the calculated power.
For correct operation, the following relationship must be met: If this relationship is not met, then
Ingeteam cannot guarantee the accuracy and correct operation of the SMART DLM:
Where:
S : Power consumption at the A65+ wattmeter expressed in VA. The power dissipated by the
w
wattmeter for rated current I
For currents other than 5 A, the power consumed by the wattmeters associated with the
measurements can be obtained as:
2
S = I x Z
w
S : The power consumed by the current transformer secondary wiring in VA. It can be calculated as:
c
The cable impedance must be considered at an ambient temperature of at least 40ºC.
Insulation level
The current transformers used must provide an insulation level of ≥ 1 kV.
When setting the parameters to define the characteristics of a current
transformer, consider the environmental operating conditions of the installation.
The secondary circuit of a current transformer in service, must never be open-
circuited
ABW2012IQM01_B
≥ S
S
n
= 5A is Sw = 0.3 VA per phase.
n
= 12 mΩ. For example: S
, where Z
w w
S = I
c
+ S
w c
2 2
= I x Z = 5 x 0.012 = 0.3VA
w w
2
x Z
c
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