General - Samlex Power DC-1000-KIT Guide D'utilisation

SECTION 2 |
The Inverter Installation Kit consists of two cables and fuse arrangement for
connecting the battery to the inverter in a safe manner.
Fuse Protection in the Battery Circuit
A battery is an unlimited source of current. Under short circuit conditions, a battery
can supply thousands of Amperes of current. If there is a short circuit along the length
of the cables that connect the battery to the inverter, thousands of Amperes of current
can flow from the battery to the point of shorting and that section of the cable will
overheat, the insulation will melt and the cable will ultimately break. This interruption
of very high current will generate a hazardous, high temperature, high energy arc
with accompanying high pressure wave that may cause fire, damage nearby objects
and cause injury. To prevent an occurrence of hazardous conditions under short circuit
conditions, an appropriate fuse should be used in the battery circuit that has the
required current interrupting capacity (Termed AIC – Ampere Interrupting Capacity).
For this purpose, a fuse with AIC rating of 10000A at 14V / 5000A at 32V, or higher
should be used.
The following types of fuses are included in the Kit:
• 400A, 125 VDC, Model JLLN 400 manufactured by Littelfuse
- AIC of 20,000A
- UL Class "T" rated, UL listed as per UL Standard 248-15
• Marine Rated Battery Fuse (MRBF Series) made by Cooper Bussmann
- Voltage rating of max 58 VDC
- Current ratings of 100A (MRBF-100), 200A (MRBF-200) and 300A (MRBF-300)
- AIC of 10000A at 14VDC, 5000A at 32 VDC and 2000A at 58 VDC
- Ignition protected as per SAE J1171
- Weather Proof (IP66)
!
CAUTION
The fuse should be placed as close to the battery's POSITIVE terminal as
possible, preferably within 7" of the battery terminal.
Sizing of Cables to Reduce Voltage Drop, Heating and Power Loss
Flow of electric current in a conductor is opposed by the resistance of the conductor.
The resistance of the conductor increases linearly as the length of the conductor is
increased and decreases as the cross-section (thickness) of the conductor is increased.
Flow of current through the resistance of the conductor produces voltage drop and
power loss due to heating. Voltage drop due to resistance of the conductor increases
linearly as the current increases.
Power loss because of heating due to resistance of the conductor increases by the
square of the increase in the current - e.g. if the current increases 2 times, the heating
/ power loss increases 4 times. Thus, it is desirable that thicker and shorter conductors
be used to reduce the undesirable effects of voltage drop, heating and power loss.
4 | SAMLEX AMERICA INC.

General